Sometimes you need to convert a number to a string because you need
to operate on the value in its string form. There are several easy ways
to convert a number to a string:
For example:
// Concatenate i with an empty string "".
String class provides the following overloaded static valueOf() methods to construct the string representation of the primitive types.
For example:
String bool = String.valueOf(false);
String ch = String.valueOf('c');
String i = String.valueOf(10);
String l = String.valueOf(100L);
String f = String.valueOf(3.14f);
String d = String.valueOf(3.14);
To convert a primitive type to a string you can use the following methods offered by the wrapper classes.
String s = Short.toString((short) 25);
String i1 = Integer.toString(100);
String i2 = Integer.toString(100, 2);
String l1 = Long.toString(1000);
String l2 = Long.toString(1000, 8);
String f = Float.toString(3.14f);
String d = Double.toString(3.14);
String bool = Boolean.toString(false);
String ch = Character.toString('c');
Notice that Integer and Long toString() methods take an additional argument, int radix, which indicates in what base (for example binary, octal, or hexadecimal) the first argument is represented.
For example,
String i1 = Integer.toString(1001,2);
Here converts binary 1001 to the corresponding decimal value 9 and assigns the string form of 9 to variable i1.
The Integer and Long wrapper classes let you convert numbers in base 10 to other bases. These conversion methods, toXxxString(), take an int or long, and return a String representation of the converted number.The toXxxString() methods offered by the wrapper classes are given below.
For example:
The output is
15 in hex=f
15 in octal=17
15 in binary=1111
100 in hex=64
100 in octal=144
100 in binary=1100100
3.14f in hex=0x1.91eb86p1
3.14 in hex=0x1.91eb851eb851fp1
Concatenate number with an empty string
For example:
int i=10;
// Concatenate i with an empty string "".
String s1 = "" + i;
Now string s1 contains the value "10".Use the static valueOf() method in String class
String class provides the following overloaded static valueOf() methods to construct the string representation of the primitive types.
public static String valueOf(char c)
public static String valueOf(boolean b)
public static String valueOf(int i)
public static String valueOf(long l)
public static String valueOf(float f)
public static String valueOf(double d)
public static String valueOf(boolean b)
public static String valueOf(int i)
public static String valueOf(long l)
public static String valueOf(float f)
public static String valueOf(double d)
For example:
String bool = String.valueOf(false);
String ch = String.valueOf('c');
String i = String.valueOf(10);
String l = String.valueOf(100L);
String f = String.valueOf(3.14f);
String d = String.valueOf(3.14);
Use Wrapper classes Static toString() method
To convert a primitive type to a string you can use the following methods offered by the wrapper classes.
Wrapper
|
Static toString() method
|
Byte
|
toString(byte value)
|
Short
|
toString(short value)
|
Integer
|
toString(int value)
toString(int value, int radix)
|
Long
|
toString(long value)
toString(long value, int radix)
|
Float
|
toString(float value)
|
Double
|
toString(double
value)
|
Character
|
toString(char c)
|
Boolean
|
toString(boolean b)
|
Void
|
None
|
For example:
String b = Byte.toString((byte) 5);
String s = Short.toString((short) 25);
String i1 = Integer.toString(100);
String i2 = Integer.toString(100, 2);
String l1 = Long.toString(1000);
String l2 = Long.toString(1000, 8);
String f = Float.toString(3.14f);
String d = Double.toString(3.14);
String bool = Boolean.toString(false);
String ch = Character.toString('c');
Notice that Integer and Long toString() methods take an additional argument, int radix, which indicates in what base (for example binary, octal, or hexadecimal) the first argument is represented.
For example,
String i1 = Integer.toString(1001,2);
Here converts binary 1001 to the corresponding decimal value 9 and assigns the string form of 9 to variable i1.
toXxxString() method(Binary, Hexadecimal, Octal)
The Integer and Long wrapper classes let you convert numbers in base 10 to other bases. These conversion methods, toXxxString(), take an int or long, and return a String representation of the converted number.The toXxxString() methods offered by the wrapper classes are given below.
Wrapper
|
Static toXxxString() method
|
Integer
|
toHexString(int value)
toOctalString(int value)
toBinaryString(int value)
|
Long
|
toHexString(long value)
toOctalString(long value)
toBinaryString(long value)
|
Float
|
toHexString(float value)
|
Double
|
toHexString(float
value)
|
For example:
public class Main { public static void main(String args[]) { String i_binary = Integer.toBinaryString(15); String i_octal = Integer.toOctalString(15); String i_hex = Integer.toHexString(15); System.out.println("15 in hex=" + i_hex); System.out.println("15 in octal=" + i_octal); System.out.println("15 in binary=" + i_binary); String l_hex = Long.toHexString(100); String l_octal = Long.toOctalString(100); String l_binary = Long.toBinaryString(100); System.out.println("100 in hex=" + l_hex); System.out.println("100 in octal=" + l_octal); System.out.println("100 in binary=" + l_binary); String f_hex = Float.toHexString(3.14f); String d_hex = Double.toHexString(3.14); System.out.println("3.14f in hex=" + f_hex); System.out.println("3.14 in hex=" + d_hex); } }
The output is
15 in hex=f
15 in octal=17
15 in binary=1111
100 in hex=64
100 in octal=144
100 in binary=1100100
3.14f in hex=0x1.91eb86p1
3.14 in hex=0x1.91eb851eb851fp1
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